Last week's answer:
John's warehouse is hosting a maths competition against warehouses in the same area. Each warehouse can only allow 10 employees to compete. John and his colleagues are taking tests to determine the 10 best people to send. John did well, but tied with James for the last spot. His manager decided to set-up a one-problem challenge, whoever got it right the fastest would win.
Knowing that "H" is equal to 10, and T is half of M, how could MATH be 42, TEAM be 40, and MEET be 37?
Answer:
MATH: 14+11+7+10 = 42
TEAM: 7+8+11+14 = 40
MEET: 14+8+8+7 = 37
(H=10; E=8; T=7; M=14; A=11)
New brainteaser:
The fish market is selling several kinds of fish. But there aren't any prices listed. You ask about the prices, but all the seller will tell you is this:
1. A pound of salmon and a pound of bass are £12.
2. A pound of bass and a pound of swordfish are £10.
3. A pound of salmon and a pound of swordfish are £8.
4. A pound of swordfish and a pound of gurnard are £5.
Each price per pound is a whole-pound amount. How much is the price per pound for each kind of fish?